Correct option is (a) 9
Given equation of curve is
y2 = αx3 − β
Since, it passes through (2, 3)
4 = 8α − β
\(\frac{dy}{dx} = \frac{3\alpha x^2}{2y}\)
Slope of tangent at (2, 3) is 2α
Slope of normal at (2, 3) = \(- \frac 1{2\alpha}\)
Given equation of normal is x + 4y = 14
Slope of normal is \(- \frac 14\)
⇒ α = 2
⇒ β = 7
Hence α + β = 9