Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
607 views
in Mathematics by (49.3k points)
closed by

If x + 4y = 14 is a normal to the curve 2y3 = αx3 - β at (2, 3), then the value of α + β is

(a) 9

(b) –5

(c) 7

(d) –7

1 Answer

+1 vote
by (48.2k points)
selected by
 
Best answer

Correct option is (a) 9

Given equation of curve is 

y2 = αx− β

Since, it passes through (2, 3)

4 = 8α − β

\(\frac{dy}{dx} = \frac{3\alpha x^2}{2y}\)

Slope of tangent at (2, 3) is 2α

Slope of normal  at (2, 3) = \(- \frac 1{2\alpha}\)

Given equation of normal is x + 4y = 14

Slope of normal is \(- \frac 14\)

⇒ α = 2

⇒ β = 7

Hence α + β = 9

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...