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In Hinsberg‘s method, the amine mixtures are separated from each other. The reagent used in this process is p-toluenesulphonyl chloride. Amines form sulphonamide when treated with the reagent.

The sulphonamide of an amine(X) is insoluble in KOH. Therefore,(X) is:

(A) CH3CH2CH2CH2NH2

(B) CH3CH2NHCH2CH3

(C) CH3CH2CH2NH2

(D) PhCH2CH2NH2

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Best answer

Correct option is (B) CH3CH2NHCH2CH3

The sulphonamides of primary (1°) amines are soluble in KOH due to presence of α-hydrogen atoms. The sulphonamides of secondary or 2° amines are not soluble in KOH due to absence of α-H atoms. Tertiary alcohols do not react with Hinsberg reagent.

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