Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
901 views
in Physics by (39.0k points)
closed by

A free particle of mass m moves in one dimension. The initial wave function of the particle is \(\psi\)(x, 0).

(a) Show that after a sufficiently long time t the wave function of the particle spreads to reach a unique limiting form given by

\(\psi(x, t) = \sqrt{m/ht} \exp (-i\pi/4) \exp(imx^2/2ht)\phi(mx/ht)\),

where \(\phi\) is the Fourier transform of the initial wave function:

\(\phi(k) = (2\pi)^{-1/2} \int \psi(x, 0) \exp(-ikx)dx\)

(b) Give a plausible physical interpretation of the limiting value of \(|\psi(x, t)|^2\).

1 Answer

+1 vote
by (39.4k points)
selected by
 
Best answer

(a) The Schrodinger equation is

and so after a long time t(\(t \to \infty\)),

(b)

Because p(k) is the Fourier transform of $(z, 0), we have

which shows the conservation of total probability. For the limiting case of t \(\to \infty\), we have 

\(|\psi(x, t)|^2 \to 0.|\phi(0)|^2 = 0\),

which indicates that the wave function of the particle will diffuse infinitely.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...