The wave function of the ground state of He+ is
where a is the Bohr radius. Let the wave function of 3H be \(\phi\)(r).
As the process of \(\beta\) decay takes place very fast, during the time period in which the 3H becomes 3He+ the wave function does not have time to change. Hence the probability that the 3He+ is in the ground state is
Initially, the 3H is in the ground state so that