An object is initially at x=-2m.it starts moving with variable velocity and its v-t graph is shown in the figure . what is the position at t = 4s

Question

An object is initially at x= -2m. It starts moving with variable velocity and its v-t graph is shown in the figure. What is the position of particle at t = 4s?

Answer 1

sol:-

We know that in the VT graph, the Area under the VT graph is equal to the Net displacement  

here net displacement = \((1/2)base*height= (1/2)*10*(5-0)+(1/2)5*(4-3)=17.5\)

in this case, the object starts from x= -2 then the final position of objects at t=5 is 

=-2+17.5=15.5m