Question

The equilibrium constant of a 2 electron redox reaction at 298 K is 3.8 x 10^–3 . The cell potential Eº (in V) and the free energy change ΔGº (in kJ mol^–1 ) for this equilibrium respectively, are

(A)    – 0.071, –13.8 

(B)   – 0.071, 13.8 

(C)   0.71, –13.8

(D)   0.071, –13.8

Answer 1

Correct option  (B) – 0.071, 13.8

Explanation:

ΔG° = –2.303 x 8.314 x 298 log (3.8 x 10^–3 )J

= 13809.3876 J = 13.809 Kg

ΔG° = –nFE°

13809.387 = –2 × 96500 x E°

E°_cell  =.071