Question

Maxwell’s modified form of Ampere’s circuital law is _______

(A) ∮ B^➙ ∙ dS^➙

(B) ∮ B^➙ ∙ dS^➙ = μ_oi

(C) ∮ B^➙ ∙ dℓ^➙ = μ_oi + μ_o∈_o(dɸ_E / dt)

(D) ∮ B^➙ ∙ dℓ^➙ = μ_oi + (1 / ∈_o)(d_q / dt)

Answer 1

The correct option is (C) ∮ B^➙ ∙ dℓ^➙ = μ_oi + μ_o∈_o(dɸ_E / dt).

Explanation:

Maxwell’s modified form of Ampere’s circuital law is

 ∮_ds B ∙ dℓ = μ_o ∫_s [J + ∈_o(dE / dt)]ds

i.e. ∮ B^➙ ∙ dℓ^➙ = μ_oi + μ_o∈_o(dɸ_E / dt)