Question

Fission of U-235 nucleus releases 200 MeV of energy. Calculate the fission rate (i.e. no. of fissions per second) in order to produce a power of 320 MW.

Answer 1

Total Energy/sec = 320 x 10⁶ J

Energy released = 200 MeV

= 200 x 1.6 x 10^-13 J = 3.2 x 10^-11 J

No. of fission/sec \(=\frac{320 \times 10^6}{3.2 \times 10^{-11}}\) = 1 x 10¹⁹