Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.4k views
in Chemistry by (39.4k points)
closed by

The specific heat of a metal is 0.11 and its equivalent weight is 18.61. Its exact atomic weight is

(a) 58.2

(b) 29.1

(c) 55.83

(d) 27.91

1 Answer

+1 vote
by (39.0k points)
selected by
 
Best answer

Correct option is (c) 55.83

Approximate atomic weight \(= \frac{6.4}{\text{sp.heat}} \)

\(= \frac{6.4}{0.11} \approx 58.2\)

Valency of the element = \(\frac{\text{At. wt.}}{\text{Eq. wt.}} = \frac{58.2}{18.61} = 3\)

Exact atomic weight = Valency x Eq. wt.

= 3 x 18.61 

= 55.83

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...