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यदि \(\begin{bmatrix} 0&1&2&3\\[0.3em] 3& 2& 1& 0 \\[0.3em] \end{bmatrix}\) तथा B \(\begin{bmatrix} 0 & 3 \\[0.3em] 1 &2 \\[0.3em]2 &1 \\[0.3em]3 &0 \\[0.3em] \end{bmatrix}\) हो, तो दिखाओ कि AB ≠ BA.

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समीकरण (i) और (ii) से स्पष्ट है :

AB ≠ BA.
इति सिद्धम्।

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