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 Evaluate \(\int xe^{(1+x^2)} dx\)

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Putting value of t and dt in equation

\(=\frac{1}{2}\int\,e^ tdt\)

\(=\frac{1}{2}e^t+C\)

Putting back t = (1 + x2)

\(=\frac{1}{2}e^{1+x^ 2}+C\)

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