The equation
2Al(s) + 3/2 O2 → Al2O3(s)
shows that
(a) 2 g of aluminium react with 3/2 g of oxygen to produce 1 g of aluminium oxide.
(b) 2 g of aluminium react with 3/2 litres of oxygen to produce 1 g of aluminium oxide.
(c) 2 moles of aluminium react with 3/2 moles of oxygen to produce one mole of aluminium oxide.
(d) 2 moles of aluminium react with 3/2 moles of oxygen to produce 7/2 moles of aluminium oxide.