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+1 vote
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in Chemistry by (41.0k points)
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According to Bohr's theory the angular momentum for an electron of 5th orbit is 

(a) \(\frac{2.5 h}\pi\)

(b) \(\frac{5 h}\pi\)

(c) \(\frac{25 h}{2\pi}\)

(d) \(\frac{6 h}{2\pi}\)

1 Answer

+1 vote
by (40.5k points)
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Best answer

Correct option is (a) \(\frac{2.5 h}\pi\)

Angular momentum mvr = n.h/2π (Here n = 5)

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