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Number of neutrons in a parent nucleus X, which gives 7N^14 after two successive B emissions,

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Number of neutrons in a parent nucleus X, which gives 7N14 after two successive B emissions, would be

(a) 6

(b) 7

(c) 8

(d) 9

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1 Answer

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Best answer

Correct option is (d) 9

5X14 → 7N14 + 2 -1e0

n = 14 - 5 = 9

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