Q.10 An aeroplane having a distance of 50 metre between the edges of its wings is flying horizontally with a speed of \( 360 km / hour \). If the vertical component of earth's magnetic field is \( 4 \times 10^{-4} \) weber \( / m ^{2} \), then the induced emf between the edges of its wings will be - (a) \( 2 mV \) (b) \( 2 V \) (c) \( 0.2 V \) (d) \( 20 V \)

Question

Q.10 An aeroplane having a distance of 50 metre between the edges of its wings is flying horizontally with a speed of \( 360 km / hour \). If the vertical component of earth's magnetic field is \( 4 \times 10^{-4} \) weber \( / m ^{2} \), then the induced emf between the edges of its wings will be - (a) \( 2 mV \) (b) \( 2 V \) (c) \( 0.2 V \) (d) \( 20 V \)

Answer 1

Correct option is (b) 2V

Induced Emf

e = B_v​vl

velocity of plane = \(\frac{3600\times 1000}{3600}=100\,m/s\)

∴ e = 4 x 10^-4 x 100 x 50

= 2 V