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If 1/x + 1/y + 1/z = 1, show that the minimum value of the function a^3x^2 + b^3y^2 + c^3z^2 is (a + b + c)^3.

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If 1/x + 1/y + 1/z = 1, show that the minimum value of the function a3x2 + b3y2 + c3z2 is (a + b + c)3.

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Let F = (a3x2 + b3y2 + c3z2) + λ(1/x + 1/y + 1/z)

we form the equations Fx = 0, Fy = 0, Fz = 0

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