Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.3k views
in Motion of System of Particles and Rigid Body by (50 points)
Obtain the formula for maximum safe speed (v max ) of a vehicle on level curved road.

Please log in or register to answer this question.

1 Answer

+1 vote
by (58.2k points)

i. Consider a vertical section of a car moving on a horizontal circular track having a radius 'r' with 'C' as the centre of the track.

ii. Forces acting on the car (considered to be a particle):

a. Weight (mg), vertically downwards,

b. Normal reaction (N), vertically upwards that balances the weight

c. Force of static friction (fs) between the road and the tyres.

Since normal reaction balances the weight

∴ N = mg ....(1)

While working in the frame of reference attached to the vehicle, the frictional
force balances the centrifugal force.

\(f_s=\frac{mv^2}{r}..(2)\)

Dividing equation (2) by equation (1),

∴ \(\frac{f_s}{N}=\frac{v^2}{rg}...(3)\)

iii. However, fs has an upper limit (fs)max = μsN, where μs is the coefficient of static friction between the road and the tyres of the vehicle. This imposes an upper limit to the speed v.

At the maximum possible speed,

\(\frac{(f_s)_{max}}{N}=μ_s=\frac{v^ {2}_{max}}{rg}\) ...[From equation (2) and (3)]

∴ \(v_{max}=\sqrt{μ_srg}\)

This is an expression of maximum safety speed with which a vehicle should move along a curved horizontal road.

iv. Significance: The maximum safe speed of a vehicle on a curve road depends upon friction between tyres and road, the radius of the curved road and acceleration due to gravity.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...