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Let r be a root of the equation x^2 + 2x + 6 = 0. The value of (r + 2) (r + 3) (r + 4) (r + 5) is equal to-

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Let r be a root of the equation x2 + 2x + 6 = 0. The value of (r + 2) (r + 3) (r + 4) (r + 5) is equal to- 

 (A) 51 

(B) – 51 

(C) –126 

(D) 126 

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1 Answer

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r is root, therefore r2 + 2r + 6 = 0 

(r + 2) (r + 3) (r + 4) (r + 5)

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