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A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x =3d. The slab is equidistant from the plates. The capacitor is given some charge. As x goes from 0 to 3d 

(a) the magnitude of the electric field remains the same 

(b) the direction of the electric field remains the same 

(c) the electric potential increases continuously 

(d) the electric potential increases at first, then decreases and again increases.

1 Answer

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by (72.4k points)
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Best answer

Correct option: (b, c)

Explanation: 

Direction of electric field is from high potential to low potential 

∴ in slab direction of electric field is downward (same as other two region so v will increase.

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