Question

01. \( 0.056 k g \) of Nitrogen is enclosed in a vessel at a temperature of \( 127^{\circ} C \). The amount of heat required: the speed of its molecules is \( kcal \) ( Take \( R =2 cal mol ^{-1} K ^{-1} \) ) 02. A \( 100 g \) of iron nall is hit by a \( 1.5 kg \) hammer striking at a velocity of \( 60 ms ^{-1} \). What will be the is temperature of the nall if one fourth of energy of the hammer goes into heating the nail? [Specific heatan

Answer 1

0.1) Because the vessel is closed, it will be an isochoric process.

To double the speed, temperature must be 4 times (v∝√T)

So T_f = 1600 K, T_i = 400 K

Number of moles are 56/28 = 2

So Q = nCvΔT = 2 x 5/2 x 2 x 1200

(For diatomic gas, C_v = 5/2 R

Q = 12000 cal = 12K cal

0.2) \(\frac{1}{2}\times 1.5 \times 60^2 \times \frac{1}{4}= 100\times 0.42 \times \triangle T\)

\(\triangle T =\frac{1,5 \times 60 ^ 2}{8 \times 100 \times 0.42} =16.07°C\)