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Change the order of integration and hence evaluate ∫∫xydydx for x, y [(0, 4a) (x2/√4a, 2ax)]

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Best answer

We have

From y = x2/4a, we get y = 0 and y = 4a

Thus the points of intersection of the parabola y = x2/4a and y = 2√ax are (0, 0) and (4a, 4a) on changing the order of integration we have y varying from 0 to 4a and x varying from y2/4a to 2√ay.

Thus

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