physice problem

Question

a)        Compute range of projectile motion. Analyze, for what angle of projection, the horizontal range will maximum?

b)       In the cricket game, a batsman strikes the ball such that it moves with the speed 30 m/s at an angle 30^o with the horizontal as shown in the Figure 5. The boundary line of the cricket ground is located at a distance of 75 m from the batsman? Investigate, will the ball go for a six? (Neglect the air resistance and take acceleration due to gravity g = 10 m s-2)

Answer 1

(a) Projectile motion: When a particle is projected obliquely near the earth surface, it moves simultaneously in horizontal and vertical directions. This type of motion is called projectile motion.

Where, u = projected speed

θ = angle at which an object is thrown from the ground.

g = acceleration due to gravity = 9.8 m/s²

Maximum Range: It is the longest distance covered by the object during projectile motion.

When the angle of projection is 45°, the maximum range is obtained.

(b) The motion of the cricket ball in air is essentially a projectile motion. As we have already seen, the range (horizontal distance) of the projectile motion is given by

This distance is greater than the distance of the boundary line. Hence the ball will cross this line and go for a six.