Question

If the peak value of any alternating current is I₀ = 5√2, then the root mean square value of alternating current (I_rms) will be

(A) 5 A

(B) 10 A

(C) 25 A

(D) 50 A

Answer 1

Correct option is (A) 5 A

Given,

\(I_0 = 5\sqrt 2A\)

Root-mean-square value of current,

\(I_{rms} = \frac{I_0}{\sqrt 2} = \frac {5\sqrt 2}{\sqrt 2} = 5A\)