Question

In ∆PQR, side QR is extended up to a point S such that ∠PRS = 150° and ∠PQR = 80°, then the value of ∠QPR is

(A) 50° 

(B) 70°

(C) 80° 

(D) 150°

Answer 1

Correct Option (B) 70°

 

Given:

\( \angle P R S=150^{\circ}\)

\( \angle P Q R=80^{\circ}\)

By Exterior angle property of triangle.

\(\angle Q P R+\angle P Q R  =\angle P R S\)

\(\angle Q P R+80^{\circ}  =150^{\circ}\)

\(\angle Q P R  =150^{\circ}-80^{\circ}\)

\(\therefore \angle Q P R  =70^{\circ}\)

Answer 2

In ∆PQR, side QR is extended up to a point S such that ∠PRS = 150° and ∠PQR = 80°, then the value of ∠QPR is (B) 70°