Question

If \( \left[ Cu \left( H _{2} O \right)_{4}\right]^{2+} \) absorbs a light of wavelength \( 600 nm \) for \( d - d \) transition, then the value of octahedral crystal field splitting energy for \( \left[ Cu \left( H _{2} O \right)_{6}\right]^{2+} \) will be (Given : \( h = 6.63 \times 10^{-34} Js \) and \( c =3.08 \times 10^{8} ms ^{-1} \) )

Answer 1

\(\Delta_t=\frac{hc}{\lambda} = \frac{6.63 \times 10^{-34}\times 3.08 \times 10^8}{600 \times 10^{-9}}\)

\(= \frac{6.63 \times 3.08 \times 10^{-17}}{600}\)

\(= 0.034034 × 10^{−17}\)

\(= 340.34 × 10^{−21 }J\)

\(\Delta_0 = \frac94\Delta_t\)

\(= \frac 94 \times340.34 \times 10^{-21}\)

\(= 765. 765 \times 10^{-21}J\)

\(\approx766\times 10^{-21}J\)

Answer = 766