Let us consider an AC circuit in which a pure resistance R connected in series with a source of alternating voltage.
Let \( V = V_0\sin \omega t\) ----- -(1) is the applied AC voltage
Where, \( V_0\) is the peak value of voltage and w is the angular velocity. \(w=2\pi f\)
Due to the applied AC voltage, A current flows in the circuit this current is given by,
\(I = V/R = \frac{V_0}{R}(\sin\omega t)\) ---- (2)
Current is maximum when \(\sin wt = ± 1\), that current is called 'peak value of current and is denoted as \(I_0\).
\(\therefore\, I_0 = V_0/R\)
(2) becomes, \(I=I_0\sin\omega t\) ------- (3)
This is the expression for current in pure resistance circuit.
