Correct option is (A) \(\frac{43}{90}\)
Let \(x=0.4 \overline{7}=0.4777\) ......(i)
Multiplying equation (i) with 10.
\(10 x=10 \times 0.4777 \ldots\)
\(10 x=4.777 \ldots\)
Subtracting eq (ii) from (i),
\(10 x-x =4.777 \ldots-0.477 \ldots\)
\(9 x =4.300 \ldots\)
\(x =\frac{4.3}{9}\)
\(x =\frac{43}{90}\)
Thus, \(0.4 \overline{7}=\frac{43}{90}\).