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x^2y^2=(x+y)5 then dy/dx

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x2y2=(x+y)5 then dy/dx

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x^2y^2=(x+y)5

x^2y^2=(x+y)5

\(\frac{dy}{dx}[\frac{2x-3y}{y}]=\frac{3x-2y}{x}\)

\(\frac{dy}{dx}=\frac{(3x-2y)y}{(2x-3y)x}\)

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