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The number of air molecules in a (5m × 5m × 4m) room at standard temperature and pressure is of the order of 

 (A) 6 × 1023 

(B) 3 × 1024 

(C) 3 × 1027 

(D) 6 × 1030

1 Answer

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Best answer

Correct option (C) 3 × 1027

Explanation:

PV = N × K × T

where K is Boltzmann constant 

105 × 100 = N × 1.38 × 10–23 × 273 

N ≈ 3 × 1027 

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