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यदि \(\mathrm{A}=\left[\begin{array}{cc}1 & 0 \\ -1 & 7\end{array}\right]\) और \(\mathrm{I}=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]\) तो k का मान निकालें जबकि A2 = 8A + kI.

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हमें पता है

\(\mathrm{A}^{2}=\mathrm{A} \cdot \mathrm{A}\)

\(=\left[\begin{array}{cc} 1 & 0 \\ -1 & 7 \end{array}\right]\left[\begin{array}{cc} 1 & 0 \\ -1 & 7 \end{array}\right]\)

\(=\left[\begin{array}{cc} 1+0 & 0+0 \\ -1-7 & 0+49 \end{array}\right]\)

\(=\left[\begin{array}{cc} 1 & 0 \\ -8 & 49 \end{array}\right] \)

\(\therefore\) \(A^2 - 8A\)

\(=\left[\begin{array}{cc} 1 & 0 \\ -8 & 49 \end{array}\right]-8\left[\begin{array}{cc} 1 & 0 \\ -1 & 7 \end{array}\right]\)

\(=\left[\begin{array}{cc} 1 & 0 \\ -8 & 49 \end{array}\right]+\left[\begin{array}{cc} -8 & 0 \\ 8 & -56 \end{array}\right] \)

\(=\left[\begin{array}{cc} 1-8 & 0+0 \\ -8+8 & 49-56 \end{array}\right]\)

\(=\left[\begin{array}{cc} -7 & 0 \\ 0 & -7 \end{array}\right]\)

\(=-7\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]\)

\(=-7 \mathrm{I}\)

इस प्रकार तुलना करने पर k = -7

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