Question

A nucleus of C¹³ breaks into C¹² and neutron. Find energy released. 

Atomic mass of C¹² = 12.000 u 

C¹³ = 13.013975 u 

n = 1.008665 u 

(1) 3.04 MeV (2) 4.1 MeV (3) 4.94 MeV (4) 6 MeV

Answer 1

Correct option: (3) 4.94 MeV

Mass defect = 13.013975 – (12 + 1.008665) = 0.00531 U 

Energy released = 0.00531 × 931 = 4.94 MeV