\(CH_4 + 2O_2 \longrightarrow \underset{22g}{CO_2} + 2H_2O\)
\(mol = \frac{22}{44} = \frac 12 \)
\(\frac{n_{CH_4}}{1} = \frac{n_{CO_2}}1\) no of moles of CH4 = \(\frac 12\)
\(n_{CH_4} = \frac12\)
\(=\frac 12 \times 100 \times 10^{-2}\)
\(=50 \times 10^{-2}\)