Maths quadratic equations pyq

Question

If z²-2z+4=0 then the value of. (z/2+2/z)²+(z²/4+4/z²)²+(z³/8+8/z³)²+-----------+(z²⁴/2²⁴+2²⁴/z²⁴) is.........

a.) 36                 b.)48                        c.)35                         d.)56

Answer 1

Given :- z² − 2z + 4 = 0 

z² + 4 = 2 x

= 1

So on

Comments

Is there any alternate way to solve this like first by finding the roots and then the  value of z then solving it