Question

The electronic configuration for Neodymium is

[Atomic Number for Neodymium 60]

(1) \([Xe]\,4f^4 \,6s^2\)

(2) \([Xe]\,5f^4 7s^2\)

(3) \([Xe] 4f^6 \,6s^2\)

(4) \([Xe]4f^15d^1 6s^2\)

Answer 1

(1) \([Xe]\,4f^4 \,6s^2\) 

Electronic configuration of Nd(Z = 60) is; 

\([Xe]\,4f^4 \,6s^2\)