Question

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is

(1) \(5,0,0,+\frac{1}{2}\)

(2) \(5,0,1,+\frac {1}{2}\)

(3) \(5,1,0+\frac {1}{2}\)

(4) \(5,1,1,+\frac {1}{2}\)

Answer 1

(1) \(5,0,0,+\frac{1}{2}\)

\(Rb = [Kr]5s^1\)

n = 5

l = 0

m = 0

\(s=+\frac {1}{2}\) or \(-\frac {1}{2}\)