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\(2Mn O ^{-} _ 4 + bI^- + cH _2O \rightarrow xI _2 + y Mn O_2 + z OH ^-\)

If the above equation is balanced with integer coefficients, the value of z is _______

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Correct answer is : 8

Adding oxidation half and reduction half net reaction is

Adding oxidation half and reduction half, net reaction is

\(2Mn O^-_4 +6I^- + 4H _2 O \rightarrow 3 I_2 +2Mn O_2 + 8OH^-\)

⇒ z = 8

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