Correct option is (2) -5
\(3 \sin \alpha \cos \beta+3 \sin \beta \cos \alpha\)
\(=2 \sin \alpha \cos \beta-2 \sin \beta \cos \alpha\)
\(5 \sin \beta \cos \alpha=-\sin \alpha \cos \beta\)
\(\tan \beta=-\frac{1}{5} \tan \alpha\)
\(\tan \alpha=-5 \tan \beta\)