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A nucleus has mass number \(A_1\) and volume \(V_1\). Another nucleus has mass number \(A_2\) and volume \(V_2.\) If relation between mass number is \(A_2 = 4A_1,\) then \(\frac {V_2}{V_1}\) = ____.

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Correct answer is : 4

For a nucleus

Volume: \(V = \frac {4}{3} \pi R ^3\)

\(R = R _0 (A)^{1/3}\)

\(V = \frac {4}{3} \pi R ^3 _0 A\)

\(\Rightarrow \frac {V_2}{V_1} = \frac {A_2}{A_1} = 4\)

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