Question

Consider an element of a stretched string along which a wave travels. During its transverse oscillatory motion, the element passes through a point at y = 0 and reaches its maximum at y = ym. Then, the string element has its maximum 

(a)   kinetic energy at y = y_m 

(b)  elastic potential energy at y = y_m 

(c)  kinetic energy at y = 0 

(d)  elastic potential energy at y = 0 

Answer 1

Correct option  (c) kinetic energy at y = 0  (d) elastic potential energy at y = 0

Explanation:

The expression for potential energy per unit volume is same as that of kinetic energy per unit volume

So the potential energy becomes maximum at y = 0 : u_max =  1/2ρω²A²

So, both potential and kinetic energies become maximum at mean position and zero at extreme position.