Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is 2y/x2 . If the curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0, then its equation is
(1) x loge | y | = 2(x – 1)
(2) x loge | y | = 2(x – 1)
(3) x2 loge | y | = –2(x – 1)
(4) x loge | y | = x – 1
