Correct option (2)
Explanation:

= \(\sqrt{2(x^2-x+19)}\)
=\(\sqrt{2(x^2-x-\frac{1}{4}+19-\frac{1}{4})}\)
\(=\sqrt{2(x-\frac{1}{2})^2+\frac{75}{4}}\)
\(=\sqrt{2(x-\frac{1}{2})^2+\frac{75}{2}}\)
\(\geq\sqrt{\frac{75}{2}}\) \((\because2(x-\frac{1}{2})^2\geq0)\)
\(= 5\sqrt{\frac{3}{2}}\)
Hence r \(\geq5\sqrt{\frac{3}{2}}\)