Question

Two dice are thrown together. The probability that they show different numbers is:

(A) \(\frac 16\)

(B) \(\frac 56\)

(C) \(\frac 13\)

(D) \(\frac 23\)

Answer 1

Correct option is (B) \(\frac 56\)

We know that when 2 dice are thrown then total no of outcome will be 36.

According to question,

Outcomes with different numbers on dice = 30

Total no. of outcomes = 36

Probability = \(\mathrm{\frac{No. \ of \ desired \ outcomes}{Total\ number\ of \ outcomes}}\)

= \(\frac{30}{36}\)

= \(\frac 56\)