Question

Consider an electric field E=E₀ x, where E₀ is a constant. The flux through the (a,0, a) shaded area due to the field is

      

(i) 2E₀ a ² 

(ii) √2 E₀ a² 

(iii) E₀ a² 

(iv) \(\frac{E_0 a^2}{\sqrt2}\)

Answer 1

Correct option is :  (iii) E₀ a²

Electric flux φ=EScosɵ 

Here ɵ=45° E=E₀ 

S= (√2a) (a) =√2a²

So, flux=E₀√2a² cos 45°= E₀ a²

Flux φ= \(\frac{q}{K\varepsilon_0}\)