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+1 vote
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in Physics by (20.3k points)
edited by

The correct products of the reaction

\(^{235}_{92}U+ ^1_0n\rightarrow\) 

are

(1) \(^{141}_{56}Ba+^{92}_{36}Kr+ 3_0^1n\) 

(2) \(^{141}_{56}Ba+^{92}_{36}Kr+ 4_0^1n\) 

(3) \(^{20}_{10}Ne+^{122}_{51}Sb+ 3_0^1n\) 

(4) \(^{20}_{10}Ne+^{122}_{51}Kr+ 4_0^1n\)

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1 Answer

+1 vote
by (20.3k points)

Correct Option is (1) \(^{141}_{56}Ba+^{92}_{36}Kr+ 3_0^1n\) 

Conserving charge and mass, we get option (1) as correct

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