Question

x g of ethylamine on reaction with NaNO₂ and HCl, produces 2.24 L of N₂(g) at NTP. The value of 2x will be 

Answer 1

Correct answer is : 9

Mole of N₂(g) produced = \(\frac{2.24}{22.4}\)= 0.1 mol 

So, mole of C₂H₅NH₂ used = 0.1 mol 

Mass of C₂H₅NH₂ = 45 × 0.1 = 4.5 g 

So, 2x = 2 × 4.5 

= 9