Correct option is : (2)
Electric field E at a distance r due to infinite long wire is \(\frac{2kλ}{r}\)
Force of electron \(\Rightarrow \mathrm{F}=\mathrm{eE}\)
\(\mathrm{F}=\mathrm{e}\left(\frac{2 \mathrm{k} \lambda}{\mathrm{r}}\right)\)
\(\mathrm{F}=\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{r}}\)
This force will provide required centripetal force
\(\mathrm{F}=\frac{\mathrm{mv}^{2}}{\mathrm{r}}=\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{r}}\)
\(v=\sqrt{\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{m}}}\)
\(\mathrm{KE} =\frac{1}{2} \mathrm{mv}^{2}=\frac{1}{2} \mathrm{~m}\left(\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{m}}\right) \)
\(=\mathrm{k} \lambda \mathrm{e}\)