Question

A rod of length 60 cm rotates with a uniform angular velocity 20 rad s^–1 about its perpendicular bisector, in a uniform magnetic field 0.5 T. The direction of magnetic field is parallel to the axis of rotation. The potential difference between the two ends of the rod is ____V.

Answer 1

Correct answer is : 0

\(\because \mathrm{V}_{0}-\mathrm{V}_{\mathrm{A}}=\frac{\mathrm{B} \omega \ell^{2}}{2}\)

\(\mathrm{V}_{0}-\mathrm{V}_{\mathrm{B}}=\frac{\mathrm{B} \omega \ell^{2}}{2}\)

\(\therefore \mathrm{V}_{\mathrm{A}}=\mathrm{V}_{\mathrm{B}} \therefore \mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=0\)