Question

9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product 'P'. The mass of product 'P' obtained is 26.4 g. The percentage yield is ……… %.

Answer 1

Correct answer is 80

93 g of aniline produces 330 g of 2, 4, 6- tribromoaniline. Hence 9.3 g of aniline should produce 33g of 2, 4, 6-tribromoaniline. Hence percentage yield \(\frac {26.4 \times 100}{33} = 80 \%.\)