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The number of moles of methane required to produce 11g \(CO_2\) (g) after complete combustion is: 

(Given molar mass of methane in g \(mol^{-1}\) : 16) 

(1) 0.75 

(2) 0.25 

(3) 0.35 

(4) 0.5

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Best answer

Correct option is (2) 0.25 

\( \mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{n}+2}+\frac{3 \mathrm{n}+1}{2} \mathrm{O}_2 \longrightarrow \mathrm{nCO}_2+(\mathrm{n}+1) \mathrm{H}_2 \mathrm{O} \)

\(\underset{\underset {0.25\,mole}{4gm}}{CH_4}+2O_2 \rightarrow \underset {\underset {0.25\,mole}{11gm}}{CO_2} + 2H_2O\)

\(0.25 \) mole \(CH_4 \) gives 0.25 mole (or 11 gm) \(CO_2\)

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