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+1 vote
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The electric field at point p due to an electric dipole is E. The electric field at point R on equitorial line will be \(\frac{E}{X}\). The value of x :

The electric field at point

1 Answer

+2 votes
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Best answer

Correct answer is : 16

\(E_{P}=\frac{2 K P}{r^{3}}=E\)

\(E_{R}=\frac{K P}{(2 r)^{3}}=\frac{E}{16}\)

\(\mathrm{x}=16\)   

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